dilluns, 14 de novembre del 2016

Data Tiering: a simple performance analysis


A certain transaction uses 1 ms of cpu time and 20 ms of IO time. With a think time of 10 s the system supports 550 users with a response time R below 1 s.

Now the same system is equipped with a faster storage where part of the data is placed. When this data replacement is automatic, the faster storage is acting as a cache. If the transaction finds the data in the cache the IO time is reduced to 5 ms. Otherwise the IO time remains to be 20 ms.  

With a hit ratio of 10%, that is, one in ten IO accesses are served from the cache, the performance of the system improves in the following ways:
  • With the same customer population (550 users) now the average response time drops from 1 s to 0.20 s!
  • The user population may increase from 550 to 611 users to reach again the limit of 1 s of average response time.


Let us build a reasonably simplified performance model for the caching in data tiering, a model suitable for a simple but illustrative performance analysis. A transaction "visits" the CPU, using C units of time (1 ms in the scenario), and "visits" the storage, using S units of time (20 ms in the scenario).





With a cache in place the same transaction may find the data in the cache -this is called a (cache) hit-, and in such fortunate case it doesn't have to visit the storage. This fast IO takes F units of time (5 ms in the scenario)


Two parameters to describe the cache effect:
  • α - efficiency  (0 <= α <= 1), defined as α=(S-F)/S or, equivalently  F=S(1-α).
  • h - hit ratio: (0 <= h <= 1), ratio of transactions that get their required data from the cache, typically proportional to its capacity.

KPI #1: Best Latency

Without the cache the best latency (response time) a transaction may achieve is Rmin=C+S units of time. With the cache in place, the best achievable latency reduces to R'min=C+F, corresponding to the transactions that get their IO from the cache.

In our scenario, the best latency with cache miss is 21 ms, and with cache hit is 6 ms.


KPI
No cache
With cache
Best Latency
C+S
hit:     C+S(1-α)
miss:           C+S

KPI #2: Bandwidth

Without the cache the bandwidth (best throughput) the system delivers is B=1/S, limited by the bottleneck device, the slow storage. With the cache in place the system is able to sustain a peak throughput of  B'=B/(1-h) for h<α and B'=B/(h·(1-α)) for h>α .

In our scenario, the bandwidth without cache is 1/20 ms-1, that is 50 transactions per second. With cache the bandwidth increases 11% for a hit ratio h=10%,  25% for h=20%, and 100% for h=50%.


KPI
No cache
With cache
Bandwidth
B=1/S
B'=B/(1-h)      if  h<=1/(2-α)
B'=B/[h·(1-α)]   if h>1/(2-α)

Here is a plot of the bandwidth gain with cache versus the hit ratio. The hit ratio that achieves the maximum bandwidth gain is h=1/(2-α), and the corresponding maximum gain is B'/B=(2-α)/(1-α).


Graph: bandwidth gain with cache (α=75%) versus the hit ratio

KPI #3: Response Time

The impact of the presence of the cache in the response time signature of the system, that is, the graph response time versus the number of users interacting with the system, is twofold:
  • a displacement to the right due to the increase of the saturation population, the point that marks the change of phase, and
  • a decrease in the high load slope.

Graph: response time versus the number of users


The consequence of these is that the the cache reduces the response time, a reduction that  is stronger in the high load zone. We must speak of averages here, as there are two response times now: one for transactions with IO is served from cache, and other for transactions with IO served from the slow storage.

In our scenario with a hit ratio of 10% the response time of the system drops from 1 s to 0.20 s with the same customer population (550 users).


KPI #4:Supported users


Looking at the response time signature from another point of view is clear that  additional users may work in the system while keeping the same level of performance (response time limit).

In our scenario the user population may increase from 550 to 611 users to reach again the limit of 1 s of average response time (see above graph).


Side effects

These performance benefits of caching don't come for free. Apart from the evident monetary cost, think about the following
  • The CPU usage increases: the cache alleviates the load on the storage but increase the load on the CPU, because if the CPU gets the data faster, it has more work to do. This may displace other cpu intensive work that may be competing for the CPU.
  • The housekeeping burden: cache housekeeping tasks (data load, data discard...) may consume CPU cycles, unless this task is offloaded to the storage.



divendres, 11 de novembre del 2016

The scalability of the software


The developers team in the ABC company has just built a five star transaction / program. The program code has a critical region. Basic performance tests with a few users result in a the total execution time of 1 s, with a residence time in the critical region of 0.05 s. These numbers are considered satisfactory by the management, so the deployment for general availability is scheduled for next weekend.

You, a performance analyst's apprentice, ask for the expected concurrency level, that is, the number of simultaneous executions of the  transaction / program. This concurrency results to be 100.

What do you think about this?

A suitable performance model

A very simple model to analyze and predict the performance of the system is a closed loop, with two stages and fixed / deterministic time in each stage, as depicted here:



The total execution time of the program is divided into:
  • the time in the parallel region, where concurrency is allowed.
  • the time in the serial (critical) region, where simultaneity is not allowed..

With only one user (one copy of the program/transaction in execution) the elapsed time is P + S, that is, 1 s ( = 0.95 + 0.05 ).

But what happens when the concurrency level is N? In particular, what happens when N=100?

And the model predicts...

Calculating as explained in "The Phases of the Response Time" the model predicts the saturation point at N*=20 (=1+0.95/0.05) users. This is the software scalability limit. More than 20 users or simultaneous executions will queue at the entry point of the critical region. The higher the concurrency level, the bigger the queue, and the more the waiting time. You can easily calculate that with the target concurrency level of 100 users, the idyllic 1 s time measured by the developers team (with few users) will increase to an unacceptable 5 s level. This means that the elapsed time of any program/transaction execution will be 5 s, distributed in the following way:
  • 0.95 s in the parallel region,
  • 4 s waiting to enter the critical (serial) region, and
  • 0.05 s in the critical region.



Elapsed execution time for N=1 and N=100 concurrency level


The graph of the execution time against the number of concurrent users is the following:
Elapsed execution time against the concurrency level


And, in effect, when the program is released  the unacceptable response time shows up!

Corrective measures

The crisis committee hold an urgent meeting, and these are the different points of views:
  • Developers Team: the problem is caused by a HW capacity insufficiency. Please, growth (assign more cores to) the VM supporting the application and the problem will disappear.
  • Infrastructure Team: hardware undersized? No point. The CPU usage is barely 25%! We don't know what is happening.
  • Performance Analyst Team (featuring YOU): more cores won't solve the problem as the hardware is not the bottleneck!  

Additional cores were assigned but, as you rightly predicted, things remained the same. The bottleneck here is not the hardware capacity. but the program itself. The right approach to improve the performance numbers is by reducing the residence time in the non parallelizable critical region. So the developers team should review the program code in a  performance aware manner.

You go a step further and expose more predictions: if the time in the critical region were reduced from the current 0.05 s to 0,02 s the new response time for a degree of simultaneity of 100 will be 1.5 s, and the new response time graph will be this one (blue 0.05 s, red 0.02 s):

Elapsed execution time against the concurrency level for S=0.05 ms (blue) and S=0.02 ms (red).

Lessons learnt

  • Refrain to blame the hardware capacity by default. There are times, more than you think, in which the hardware capacity is not the limiting factor, but an innocent bystander that gets pointed as the culprit.
  • Plan and execute true performance tests in the development phase, and specially a high load one, because with few users you probably will not hit the performance bottleneck.
  • Definitively welcome the skills provided by a performance analyst. Have one in your team. You won't regret.